-3x^2-2x+30=0

Solution for -3x^2-2x+30=0 equation:

-3x^2-2x+30=0

a = -3; b = -2; c = +30;
Δ = b2-4ac
Δ = -22-4·(-3)·30
Δ = 364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{364}=\sqrt{4*91}=\sqrt{4}*\sqrt{91}=2\sqrt{91}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{91}}{2*-3}=\frac{2-2\sqrt{91}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{91}}{2*-3}=\frac{2+2\sqrt{91}}{-6}
$